(5-12)
(5-12)
① The peak widths at half height are straightforwardly found, just as 2 x the positive intercepts on the line F(x) = 0.5:
kmax : 0.5 1.0 2.0 5.0
x: 2.80 1.40 0.70 0.28
Δx½: 5.60 2.80 1.40 0.56
② Looking at these numbers, you can readily see that, for example, when kmax is doubled, Δx½ halves: there appears to be a reciprocal relationship. This is confirmed by plotting 1/Δx½ against kmax :
From the gradient of the graph, we can quantify this relationship as: 1/Δx½ = 0.71 kmax
and hence: Δx½ = 1 / 0.71kmax = 1.4 / kmax